Problem Description

珊珊終於學成歸國了,文文的考驗時刻也到了。走出了迎客大廳,珊珊問:「What type of year was I born in?」文文很有自信的回答:「閏年!」可是珊珊卻說:「No, It was a LEAP YEAR!」看來文文要娶到珊珊,還得先把英文練一練。  

The Input

輸入有若干行。輸入的每一行有一個正整數 y,代表珊珊生日的西元年份。輸入以 EOF 作為結束。

The Output

對於所輸入的每個 y,要各別輸出一行。若 y 是閏年,請於該行輸出「a leap year」,否則請輸出「a normal year」。

Sample Input

1992
1993
1900
2000

Sample Output

a leap year
a normal year
a normal year
a leap year

-----* Problem from【ZeroJudge, an Online Judge System For Beginners

My Answer

 
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  #include<iostream>
using namespace std;
int main(void)
{
  int y;
  while(cin>>y && (!cin.eof())){
    if(y%4==0 && y%100!=0 || y%400==0)
      cout<<"a leap year"<<endl;
    else cout<<"a normal year"<<endl;
  }
  return 0;
}
 

 


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